Exercise 3: Recall that at average speed v, the distance d traveled in a time t is given by d = vxt Part 1 Two trains leave at the same time. The first train leaves from station A and goes to station B at 60km / h The second train leaves from station B and goes to station A at 90km / h The two stations are 300 km apart We want to know after how long will they meet. 1) Conjecture the answer 2) We propose to prove the result using an equation. Let t be the time sought. a) Check that the first train will have covered a distance of 60t b) What will be the distance traveled by the second train? c) What does the expression 300 - (60t + 90t) represent? d) Solve the equation 300 - 60t + 90t) = 0 and conclude Part 2 Max and Min are 16 km away Max goes towards Min at 5km / h and Min goes towards Max at 7 km / h. They leave at 10h 30min What time are they going to meet? And how far from the starting point of Min and Max?​

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

20 feet per second

hope i

-lavira : )

step-by-step explanation:

total income = price of one ticket   *   number of tickets sold

  y                 =     4                                   x

so the equation is y=4x     with x≥0   because number of tickets sold can not be negative

thus the equation is a semi -line with an end point at

(0,0)

passing through :

x=1     y=4(1) = 4   so through (1,4)

12 dolars one is cheaper becasue 3 pairs is 6 means is sock is 2 while the 12 is cheaper