The velocity of sound in air is given by the equation V equals 20 square root 273+ T, where V is the velocity in meters per second and T is the temperature in degrees Celsius. a.) Find the temperature when the velocity of sound in air is 420 m/s. Round the answer to the nearest degree.
b.) Find the velocity of sound in meters per second when the temperature is 40°C. Round the answer to the nearest meter per second.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

here is the

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