PCl5 (g) ⇌ PCl3 (g) + Cl2 (g) For the reaction at equilibrium, if the volume of the container is increased, the amount of PCl5 present will

a.
decrease.

b.
stay the same.

c.
triple.

d.
increase.

e.
double.

If 0.20 mole of Cl 2 is added to the equilibrium mixture, will the concentration of PCl 5 increase or decrease? If the equilibrium constant for this reaction is expressed in terms of concentrations, written as follows: Here, , and represent the molar concentrations of, , and respectively. Chapter 10, Problem 60CQ is solved.

Step-by-step explanation:

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!