Each choice compares two expressions. Choose ALL pairs of expressions that are equivalent. A) y + y + y = 3y B) 2c − 5 = (c × c) − 5 C) k2 + 3j = k + k + j + j + j D) 3x + 2y = (x × x × x) + (y × y) E) a3 + 2b = (a × a × a) + (b + b)

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.