How much money will there be in an account at the end of 10 years if $3000 is deposited at 3% interest compounded semi-annually? (Assume no withdrawals are made. Use the formula A=P
-p(1-4)
for compound interest,

$4040.57

Step-by-step explanation:

A=P(1+(r/n))^nt

P = Principal = 3000

r = rate = 0.03

n = no. times payed each year = 2

t = years = 10

A = 3000(1 + (0.03/2))^(2x10)

A = 3000(1.015)^20

A = 4040.57 (2.d.p)

Hope this helped!

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911