a skydiver jumps out from the plane at 10,000 feet above the ground. the skydiver decends at a rate of 175 feet per seconds. how high in the air is the skydiver when he opens his parachute after 25 seconds?

5625 feet

I hope it's helps you

5625 feets

Step-by-step explanation:

Rate(feet/seconds) = height(feets)/time(seconds)

175 = x/25

x = 4375

After the skydiver opens his parachute the height reduces

Initial height – reduced height

10000 – 4375

= 5625 feets

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.