Consider the function f(x) = - 4x2xs-1
-3-*-1, *> -1
Which statement explains the continuity of the function at x = -1?
Because lim f(x) = 4 and f(-1) = 4, it follows that lim f(x) = f(-1). Therefore, the function is continuous at x
1.
*--1
*--1
O Because lim f(x) = -4 and f(-1) = -4, it follows that lim f(x)=f(-1). Therefore, the function is continuous at
-1.
*--
X-1
--
O Because lim f(x) = 4 and f(-1) = -4, it follows that lim f(x) f(-1). Therefore, the function is not continuous
*--1
= -1.
O Because lim f(x) = -4 and f(-1) = 4, it follows that lim f(x) f(-1). Therefore, the function is not continuous a
= -1.
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--1

As part of an annual fundraiser to raise money for diabetes research, diane joined a bikeathon. the track she biked on was 1,920 yards long. diane biked 38.5 laps. her sponsors agreed to donate an amount of money for each mile she biked. how many miles did she bike? first fill in the blanks on the left side using the ratios shown. then write your answer. given ratios: 5280ft / 1 mi , 1 mi /5280 ft , 1,920 yards / 1 lap , 1 lap / 1,920 yards , 3 ft / 1 yard , 1 yard / 3 ft. blanks: 38.5 laps / 1 yard x (blank) x (blank) x (blank) = (blank) miles i'm really confused on how to do this, and the explanations aren't exactly . if you could walk me through how to do this, it would be greatly appreciated.

For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]

How do you find the distance of each number from the mean