The first term of a sequence is 4 and the common ratio is -2. What is the formula for the sequence
based on term number
Qy --2-(4)-1
ay -4.(-2)2-1
an = (4.-2)^2=1
an - 4.(-2)

Actually Welcome to the concept of Geometric Progression.

So, we know that,

GP = a.r^(n-1)

here, a = 4 and r = -2

so we get as,

an = 4.(-2)^n-1

Option B.) is correct

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: