A gas measuring 525 mL is collected at 104.66 kPa. What volume does this gas occupy if the pressure is increased by 25 kPa?

Recall the ideal gas law:

P V = n R T

where

P = pressure

V = volume

n = number of gas molecules

R = ideal gas constant

T = temperature

If both n and T are fixed, then n R T is a constant quantity, so for two pressure-volume pairs (P₁, V₁) and (P₂, V₂), you have

P₁ V₁ = P₂ V₂

(since both are equal to n R T )

Solve for V₂ :

V₂ = P₁ V₁ / P₂ = (104.66 kPa) (525 mL) / (25 kPa) = 2197.86 mL

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

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