Question 7: 10 pts The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2001 there were about 1,200 fish.
Write an exponential decay function to model this situation. Then find the population in 2006.
O y = 1,200(0.95)
The population in 2006 will be about 928.54 fish.
O y = 1,200(0.05)
The population in 2006 will be about 300 fish.
O y = 1,200(0.5)5
The population in 2006 will be about 38 fish.
O y = 1,200(0.95)
The population in 2006 will be about 929 fish.
908

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .

sure i'm up for it

step-by-step explanation:

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder

12 cups   is the answer

step-by-step explanation: