A ladder needs to reach a second-story window that is 15 feet above the ground and make an angle with the ground of 66°. How far out from the building does the base of the ladder need to be positioned?
Round your answer to the nearest tenth.
The base of the ladder needs to be feet away from the wall.

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute:

teleportation

step-by-step explanation: