Integers is ind the integers.
6. Of three consecutive odd integers, k is the middle one. If the difference between
the products of the last two and first two is 28, find the three integers.
7. A man divides his savings amongst his son daughter and wife. His wife get​

See below

Step-by-s.ep explanation:

6. Let the 3 integers be k-2, k and k+2.

So k(k+2)-k(k-2) = 28

k^2 + 2k - k^2 + 2k = 28

4k = 28

k = 7.

So the 3 integers are 5, 7 and 9.

answer: idk

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.