Complete the following proof. Given: AE is tangent to circle R at point A and to circle S at point E

Proven: ∠R = ∠S

5x+10 is the correct one

hope this

answer: sorry i can't you.

step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

i need a picture

step-by-step explanation: