HELP ME PLEASE ITS FOR MY NEXT YEARS CLASS A local park currently has 150.04 square meters of grassy area. The members of a community group have proposed the following changes to the way the park land is used.

Clearing dead trees and shrubs would allow for 37.51 square meters of additional grassy area.
Removing an unused picnic pavilion would allow for 82.70 square meters of additional grassy area.
Updating and expanding the playground would reduce the grassy area by 54.19 square meters.
How many square meters of grassy area would the park have if all of the community group's proposals were applied?

A.
66.02 square meters
B.
95.85 square meters
C.
216.06 square meters
D.
249.42 square meters

they would have 216.06 square meters of grassy area left in the park

Step-by-step explanation: if you start with 150.04 and add 37.51 by removing trees and shrubs you would have 187.55 and then if you added 82.70 more square feet by removing the unused Picnic pavilion you would have 270.25 square meters of grassy area. Then lastly is you update the playground by reducing 54.19 square meters ( 270.25-54.19) you would get left with 216.06 square meters of grassy area :)

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.