Height of 10th grade boys is normally distributed with a mean of 63.5 in. and a standard deviation of 2.9 in.
The area greater than the Z-score is the probability that a randomly selected 14-year
old boy exceeds 70 in.
What is the probability that a randomly selected 10th grade boy exceeds 70 in.?

P(Z>2.24) = P(70<X<1e99) = 1.25%

Step-by-step explanation:

Calculate Z-score:

Z=(x-μ)/σ

Z=(70-63.5)/2.9

Z=6.5/2.9

Z=2.24

Find area greater than Z-score:

P(Z>2.24) = P(70<X<1e99) = normalcdf(70,1e99,63.5,2.9) = 0.0125

So the probability that a randomly selected 10th-grade boy exceeds 70 inches is a 1.25% chance.

step-by-step explan mxfcg'k; uafwgzfgjhklhgation:

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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