X is 6 or less and more than – 5 A: – 5 <
x
≤ 6 B: – 5 >
x
≤ 6 C: – 5 ≤
x
≤ 6 D: – 5 <
x
< 6 E: – 5 ≤
x
< 6

Me solve this problem, and someone clearly explain to me how to solve it.1.) use the value of the discriminant to determine if the given trinomials has 2 real solutions, 1 real solution, or no real solutions.a.  x2  − 4x  − 7 = 0b. 4r2  + 11r  − 3 = 0c. 3m2  + 7 = 0d.  t2  + 2t  + 1 = 0