Mathematics, 02.05.2021 06:30 lolll52
PLEAASEEE HELLL I DON'T GET IT ;((
Given: ∆AKL, AK = 9
m∠K = 90°
m∠A = 60°
m∠L = 30°
Find: P∆AKL, The area of ∆AKL .
Answers: 1
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PLEAASEEE HELLL I DON'T GET IT ;((
Given: ∆AKL, AK = 9
m∠K = 90°
m∠A = 60°...
m∠K = 90°
m∠A = 60°...
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