A random sample of the price of gasoline from 40 gas stations in a region gives the statistics below. Complete parts​ a) through​ c). y overbarequals​$3.59​, sequals​$0.26 ​a) Find a 95​% confidence interval for the mean price of regular gasoline in that region. (nothing comma nothing )​(Round to three decimal places as​ needed.) ​b) Find the​ 90% confidence interval for the mean. (nothing comma nothing )​(Round to three decimal places as​ needed.) ​c) If we had the same statistics from a sample of 80 ​stations, what would the​ 95% confidence interval be​ now? (nothing comma nothing )​(Round to three decimal places as​ needed.)

5104.38 inches

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term