Find the equation of the line that is perpendicular to y = - 1/3 x + 2 and passes though the point (-5,2)

y - 2 = 3(x + 5)

Step-by-step explanation:

The given equation has slope -1/3.  Any line perpendicular to the given line has a slope which is the negative reciprocal of -1/3, which comes out to +3.

Use the point-slope formula y - k = m(x - h):

y - 2 = 3(x + 5)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8