Given {5,-4,3,6}{x, y}={12,66} what is |Ax|? |12 -4
|3 6|

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4x and 6y

im not sure though

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb