A cone has a volume of 12 pi and a radius of two what is the height

h = 2.86

Step-by-step explanation:

Given: Cone; Volume = 12pi, raduis = 2

To find: The height

Formula:

Solution: Triple the volume amount. For this cone, the volume is 12. Multiplying the volume by 3 results in 36.

×  

Square the radius, and then divide the radius squared into the tripled volume. The cone's radius is 2. The square of 2 is 4, and 36 divided by 4 is 9.

÷

Divide the resulted amount calculated by pi, which is 3.14, to calculate the cone's height. 9 divided by pi results in 2.86.

÷

Therefore, the height of this cone is 28.6.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.