James bought a new car 4 years ago for $21.450. After 1 year, the car's value had depreciated to $17,589. After 2 years, its value had depreciated to $14,422.98. Today, James received an offer of $8,500 to sell his car.
Assuming the car kept depreciating at the same rate, should James accept?

1. Yes, James should accept the offer since his car is worth $7.952.37 today.

2. No, James should not accept the offer since his car is worth $9.698.01 today.

3. Yes, James should accept the offer since his car is only worth $6.006.00 today

4. No, James should not accept the offer since his car is worth $3,861.00 today.

5. There is not enough information to answer this question

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

1) is right

step-by-step explanation:

it is x equals 3   plese mark me really need it

step-by-step explanation:

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200