Can someone show me how to do this? You have to find the side length or angle measure.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

150.6

all i did was i multiplied 5.02 by 30

he has 140 chickens because he has 10 times more chickens than ducks and he has 14 ducks so 14*10=140