Write the equation of the line that passes through the points (7, -3) and (7, 0).

x = 7

Step-by-step explanation:

Since the x- coordinates of the 2 points are equal, both 7 , then the line is vertical with equation

x = c

where c is the value of the x- coordinates the line passes through, then

x = 7 ← equation of line

I hope this is right, im not sure because they are coincides or the same lines when overlapped, but I tried.

3x+0

Step-by-step explanation:

Using the formula mx+b we can get our answer.

We know that the two points pass through (7, 0)

mx+b is (slope)x+(y-intercept)

The slope of the two lines is 3 so we can replace m for 3:

3x+b

the y-intercept does not exist for these two lines as they are coincides, so we can just put it at 0, so we now have our equation 3x+0.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)