4. Given: BAC = BCA
CD bisects BCA
AE bisects BAC
Prove: ADC = CEA
help!!

Given. 2. A bisector cuts a segment into 2. ≅ parts. 3. Intersecting lines form vertical ∠. 4. ... 3. ∠ABC = ∠ADC Angle. 4. ∆ABC ≅ ∆ADC. Reasons. 1. Given. 2. Given ... AE ≅ DF. AB ≅ CD. Prove: EC ≅ FB. Statement. 1. ∠A and ∠D are a rt ∠ ... CD bisects ∠BCA ... ∠ECA ≅ ½∠BAC and ... Given: CEA ≅ CDB, ∆ABC.

Step-by-step explanation:

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

step-by-step explanation: