The maximum walking speed S, in feet per second, of an animal can be modeled by the equation S=[gL, where g=32ft/sec and L is the length, in feet, of the animals leg. To the nearest hundredth, how many times greater is the maximum walking speed of a giraffe with a leg length of 6 feet than a hippopotamus with a leg length of 3 feet? (a. 0.71 times) b 4.06 times)c.1.41 times)d.2.00 times. HELP ASAP.

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%