One zero of f(x)=x^3-2x^2-5+6 is 1 what are the other zeros of the function

the other zeros of this function are {-2, 3}

Step-by-step explanation:

Use synthetic division to find the roots.  The coefficients of this cubic function are 1, -2, -5, 6, and we begin by using 1 as our first divisor:

1    /    1    -2    -5    6

               +1      -1    -6

         1     -1       -6    0

Because the remainder is zero (0), we can conclude that 1 is indeed a root of the given polynomial.  The quotient is 1x^2  - 1x  - 6, whose roots can be found either through synthetic division or factoring.  In this case the factors are (x - 3) and (x + 2), so the other zeros of this function are {-2, 3}.

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.