PLEASE HELP ME Consider a triangle ABC has the following measures:
B
6 m
AB = 6m
BC = 4
mZA - 339
4 m
33
с
(figure may not be drawn to scale)
Two distinct triangles can be
created using those measures.
What is the measure of the side AC
for each triangle? (Round to the nearest tenth.)
Triangle 1: (AC), - 8.1 m
Triangle 2:(AC), - 3.7 m
Triangle 1:(AC), = 7.3 m
Triangle 2: (AC), - 2.7 m
Triangle 1:(AC), - 7.2 m
Triangle 2:(AC), - 3.4 m
Triangle 1:(AC), - 73 m
Triangle 2:(AC), = 3,1 m

x=half

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

46

step-by-step explanation:

given

height = 168 cm

formula

height =2.47*f+54.13

solution

168 = 2.47f + 54.13             subtract 54.13 from both sides

168 - 54.13   = 2.47f             combine

113.87 = 2.47f                     divide by 2.47

113.87 / 2.47 = f                   combine

46.1 = f  

answer: 46 cm