Mathematics, 07.05.2021 21:20 tateandvioletAHS14AY

Subtract: $\frac{6}{2x^2+8x} -\frac{x}{4x^2+12-16} =\frac{6}{2x(x+4)} -\frac{x}{4(x+4)(x-1)} =\frac{62(x-1)}{2x(x+4)2(x-1)} -\frac{xx}{4(x+4)(x-1)x}$ A: $\frac{-2x^2+12x-12}{2(x+4)(x-1)}$
B: $\frac{-x^2+6x-6}{2(x+4)(x-1)}$
C: $\frac{-2x^2+12x-12}{4(x+4)(x-1)}$
D: $\frac{-x^2+12x-12}{4x(x+4)(x-1)}$

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Another question on Mathematics

Subtract: $\frac{6}{2x^2+8x} -\frac{x}{4x^2+12-16} =\frac{6}{2x(x+4)} -\frac{x}{4(x+4)(x-1)} =\frac{62(x-1)}{2x(x+4)2(x-1)} -\frac{xx}{4(x+4)(x-1)x}$ A: $\frac{-2x^2+12x-12}{2(x+4)(x-1)}$
B: $\frac{-x^2+6x-6}{2(x+4)(x-1)}$
C: $\frac{-2x^2+12x-12}{4(x+4)(x-1)}$
D: $\frac{-x^2+12x-12}{4x(x+4)(x-1)}$