Eginning at 15,000 feet, a commercial jetliner begins climbing at a rate (in feet per minute) given by f(t)=e0.4t+8 f ( t ) = e 0.4 t + 8 with 0≤t≤20 0 ≤ t ≤ 20 where t t is the time in minutes since the aircraft began climbing. Use the Net Change Theorem to determine the aircraft's elevation after climbing for 15 15 minutes. Round the answer to the nearest foot.

im not quite sure if this is right but i got 5.6 oisutuve

step-by-step explanation:

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

b

step-by-step explanation: