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Mathematics, 10.05.2021 01:20 BluHope19

Use inverse function to be solved in in interval

$0 \leqslant x < 2\pi$
$6 \sin ^{2} x + (4 - 3 \sqrt{3} ) \cos x + 2 \sqrt{3} - 6 = 0$

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Use inverse function to be solved in in interval

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