A(4,10) and B (6,12)
(1) Find the distance between A and B

2.8284

Step-by-step explanation:

Input Data :

Point 1(xA,yA)(xA,yA) = (4, 10)

Point 2(xB,yB)(xB,yB) = (6, 12)

Objective :

Find the distance between two given points on a line?

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(6−4)2+(12−10)2(6-4)2+(12-10)2

= √22+2222+22

= √4+44+4

= √88 = 2.8284

Distance between points (4, 10) and (6, 12) is 2.8284

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