Assume f is a one to one function of f(x)= 4-6x find f^-1(-32)​

f^-1(-32)=6

Step-by-step explanation:

Find the inverse of the function f(x)=4-6x:

f(x)=4-6x

y=4-6x

x=4-6y

x-4=-6y

(x-4)/-6=y

-1/6x+2/3=y

y=-1/6x+2/3

f^-1(x)=-1/6x+2/3

Plug in f^-1(-32) for f^-1(x) and simplify:

f^-1(-32)=-1/6(-32)+2/3

f^-1(-32)=16/3+2/3

f^-1(-32)=18/3

f^-1(-32)=6

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

c

-by-step explanation:

it would be c