Find the slope of the line through the given points.* (-13, 10), (10, -13)

Work Shown:

Let's apply the slope formula to get...

m = (y2 - y1)/(x2 - x1)

m = (-13 - 10)/(10 - (-13))

m = (-13 - 10)/(10 + 13)

m = -23/23

m = -1

The slope is -1

Extra info:

The slope is the rate of change. Specifically it's the change in y over the change in x. So that's why we divide the (y2-y1) over the (x2-x1). The (y2-y1) is the change in y; the (x2-x1) is the change in x.

You can think of it as

slope = rise/run

rise = y2-y1 = change in y

run = x2-x1 = change in x

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841