Find the value of X and Y that make these triangles congruent by the HL theorem.

x=5, y=6

Step-by-step explanation:

By the HL theorem, if the corresponding hypotenuses and one side of two triangles are equal, they are congruent.

So put the hypotenuses equal to each other, and put the side lengths equal to each other.

3x-2=2y+1

x=y-1

Sub 'y-1' into the first equation for x:

3(y-1)-2=2y+1

3y-3-2=2y+1

y=6

x=y-1=6-1=5

answer: slight chance that it will happen

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.