Trapezoid EFGH has vertices E (-3, 2), F (-3, 4), G (1,4), and H (2, 2). Find the image matrix for a 180° rotation of EFGH about the origin. Graph EFGH and its image. Identify
the coordinates of the vertex G'.

G’ has coordinates ...

PLS HELP

maybe i can

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

any of them that add up to 180 degrees.