A circus acrobat is shot out of a cannon with an initial upward speed of 50 . The equation for the acrobat's pathway can be modeled by the equation h = - 16t ^ 2 + 50t + 4 . a. Find the maximum height of the acrobat.

b. How long will it take to reach the ground?

Step-by-step explanation:

h = - 16t ^ 2 + 50t + 4

maximum height  take the first derivative of h (calculus if you are taking it)

h' = -32t + 50          set this equal to zero

0 = -32t +50

t = 50/32

t = 1.5625      now plug t = 1.5625  into the height equation

h = - 16(1.5625) ^ 2 + 50(1.5623) + 4

h = 43.0625 ft

you can also find the maximum height by graphing the function and locating the peak value  (much easier)

how long to reach the ground  h = zero

0 = - 16(t) ^ 2 + 50(t) + 4

use the quadratic equation to solve this or graph the function h(t) and find the roots (much easier) and you will find that

t = -0.078 and 3.203 seconds

    obviously the negative root makes no sense unless he time travelled so

t = 3.203 seconds

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

is should be y = 5x

step-by-step explanation:

correct me if im wrong