A researcher studying microorganisms has discovered a strain of bacteria that doubles every 2.8 days. How many bacteria will the researcher have after 7.3 days if they started with 650 bacteria?

3960.4 bacteria

Step-by-step explanation:

The formula to solve the above question is given as:

P(t) = Po (2) ^t/k

P(t) = Population after time t = ?

Po = Initial population = 650 bacteria

t = Time in days = 7.3 days

k = doubling time = 2.8 days

P(t) = 650 × (2)^7.3/2.8

P(t) = 650 × 2^2.6071428571

P(t) = 650 × 6.0929582599

P(t) = 3960.4228689 bacteria.

Approximately = 3960.4 bacteria

Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb