The sides of a polygon are 3cm,5cm,6cm,8cm and 10cm. The perimeter of a similar polygons is 48cm. Find the sides of the second polygon.

Step-by-step explanation:

From the question we are told that:

Sides of Polygon 1

 a=3

 b=5

 c=6

 d=8

 e=10

Perimeter of polygon 2 P_2=48

Generally the equation for Polygon 1 is mathematically given by

 P_1=a+b+c+d+e

 P_1=3+5+6+8+10

 P_1=32

Generally the sides of similar polygon with Perimeter P_2=48 is mathematically given by

Side\ of\ polygon\ 2 =\frac{side\ of\ polygon\ 1}{perimeter\ of\ polygon\ 1}*perimeter\ of\ polygon\ 2

Therefore

not solvable

step-by-step explanation:

we need more information, or at least an

idk

step-by-step explanation: