State of the given functions are inverses. Part 3. NO LINKS​

9.

h(x)=-x-1

let y =-x-1

interchanging role of x & y

x=-y-1

y=-x-1

h-¹(x)=-x-1

again

f(x)=(2-3x)/2

let

y=(2-3x)/2

interchanging role of x & y

x=(2-3y)/2

2x-2=-3y

y=(2-2x)/3

f-¹(x)=(2-2x)/3

Given function are not inverse of each other.

10.

f(x)=-x+3

let y=-x+3

interchanging role of x & y

x=-y+3

y=3-x

f-¹(x)=-x+3

equal to g(x)=-x+3

Given function are inverse of each other.

Step-by-step explanation:

Call h(x) = y (It's easier to see).

y = -x - 1

The first step is always to interchange x and y

y = -x - 1

-x = y - 1

Solve for y

-x + 1 = y

If I understand the question, these two (f(x) and h(x)) are not inverses.

10 is a bit tricky. An inverse can invert into itself: This is called an involution. But if they are differently labeled, I'm not sure. I don't think that this is exactly what is men by an involution. Something like y = x would be. But you have 2 different inverses. I'm not sure that this qualifies.

y = x + 3      

g = x + 3

x = y + 3

x - 3 = y

explanation:

remove parenthesis:

=

apply rule

=

multiply fractions:

=

=

divide:

=

mordancy.