Solve the system by substitution
5x+y=-14
5x- 3y=2

x = -2, y = -4, or (-2, -4).

Step-by-step explanation:

5x + y = -14

5x - 3y = 2

If we look at the first equation, we can see that y can be easily isolated.

5x + y = -14

Subtract 5x from both sides.

y = -5x - 14

Now we have a variable that we can plug into the second equation.

5x - 3y = 2

5x - 3(-5x - 14) = 2

Distribute the -3 across each term in the parentheses.

5x + 15x + 42 = 2

Combine like terms.

20x + 42 = 2

Subtract 42 from both sides.

20x = -40

Divide both sides by 20 to isolate x.

x = -2

Plug in x = -2 back into one of the equations to find y.

y = -5x - 14

y = -5(-2) - 14

Multiply.

y = 10 - 14

Subtract.

y = -4

Our solution is x = -2, y = -4, or (-2, -4).

Check your answer by plugging both values into one of the equations.

5x - 3y = 2

5(-2) - 3(-4) = 2

-10 + 12 = 2

2 = 2

Your answer is correct.

Hope this helps!

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.