What is the equation of a circle with center at (4, -2) and a radius of 7?

let h= 4, k=-2 and r= 7 then

(x-h)^2 + (y-k)^2 = r^2

(x-4)^2 + (y+2)^2 = 7^2

x^2 -8x +16 + y^2 +4y +4 = 49

x^2 +y^2 -8x +4y +16 +4-49 = 0

x^2 + y^2 -8x +4y -29 = 0 is the required eq

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

addition

step-by-step explanation: