1)factorize X^-3x-10
2) factorize 2x^+6x

1.Given:

x

2

−

3

x

−

10

Find a pair of factors of

10

which differ by

3

.

The pair

5

,

2

works in that

5

⋅

2

=

10

and

5

−

2

=

3

Hence we find:

x

2

−

3

x

−

10

=

(

x

−

5

)

(

x

+

2

)

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

first one because it can't have a fraction in it

step-by-step explanation: