URGENT!! The length of a rectangle is five more than double the width. Find the dimensions if the
perimeter is 88m.

13, 31

Step-by-step explanation:

Set the width as x.

Length: 2x + 5

Perimeter:

(x) + (2x + 5) + (x) + (2x + 5) = 88

Simplify.

6x + 10 = 88

Solve.

6x = 78

x = 13

Substitute this into the previous equations

Width: 13

Length: 31

The length is 31m and the width is 13m.

Step-by-step explanation:

Start by translating the word problem into an equation. 5 more than double the width is written as 2w + 5. Then substitute that into the equation for the perimeter. It should look something like this:

88 = 2(2w +5) + 2w

Then simplify by combining like terms and solve for the width (w).

88 = 6w + 10

78 = 6w

13 = w

Now that we have the width, we can plug it back into the equation we made for the length.

l = 2w + 5

l = 2(13) + 5

l = 26 + 5

l = 31

I hope this could help!

tigers

step-by-step explanation:

cougars 12/10 (12-10 = 2)

bobcats 20/10 (20-10 =10)

bulldogs 8/5 (8-5 =3)

tigers 3/5 (3-5 =-2)

i got 86 for this

hope this !

if you need an explanation just ask