An isosceles right triangle is inscribed in a circle. The hypotenuse of the triangle is the diameter of the circle. Write a function f in terms of x that represents the area of the shaded region. Leave your answer in terms of π.

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  f(x) = (π-2)x^2/4

Step-by-step explanation:

The area of the triangle is ...

  A = 1/2(x)(x) = (1/2)x^2

The hypotenuse of the triangle is x√2, so the radius of the circle is x/√2. That means the area of the semicircle is ...

  A = 1/2πr^2 = (π/2)(x/√2)^2 = (π/4)x^2

The shaded area is the difference between the semicircle area and the triangle area.

  f(x) = (π/4)x^2 -(1/2)x^2

  f(x) = (π-2)x^2/4

the first one, all those points on the line just make a strait line.

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.