Quadrilateral RUST has a vertex at R(4,2). What are the coordinates of R'after the translation (x, y) + (x - 1, y - 1).
followed by a dilation by a scale factor of 2, centered at the origin?
O A. (6,1)
O B. (7,3)
C. (6,2)
O D. (8,2)

it is C

Step-by-step explanation:

Translation: (4,2) -> (3,1)

Dilation: (3,1) -> (6,2)

i know the answer is 3

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.