6. A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softbal's acceleration is - 16
Ft/s2. This can be modeled with the equation (h=height, t=time) h(t)=16t^2 +50t+ 3
What is the time at which the softball would hit the ground it it were not hit or caught?

A.) .5 seconds
B.)3.12 seconds
c.) 3.18 seconds
D. ) 2.42

Using their equation and the fact that the ball will fall 3 ft before reaching the ground:

3 = 16 t^2 + 50 t + 3  represents the given situation

16 t^2 + 50 t = t (16 t + 50) = 0

16 t + 50 = 0

t = 50 / 16 = 3.12 sec

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)