Find the term named in the problem geometric sequence and series 1). -3,-6,-12,-24 find a10

2). -2,6,-18,54 find a12

See explanation

Step-by-step explanation:

The nth term of a geometric progression is calculated by:

= ar^n-1

1). -3,-6,-12,-24 find a10

a = first term = -3

r = common ratio = -6/-3 = 2

n = 10

Using the formula

a10 = ar^n-1

a10 = -3 × 2^10-1

a10 = -3 × 2^9

a10 = -3 × 512

a10 = -1536

2). -2,6,-18,54 find a12

a = first term = -2

r = common ratio = 6/-2 = -3

n = 12

Using the formula

ar^n-1

a12 = -2 × -3^12-1

a12 = -2 × -3^11

a12 = -2 × -177147

a12 = 354294

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