The number of minutes needed to solve an exercise set of variation problems varies directly as the number of problems and inversely as the number of students working on the solutions. It takes 4 students 36 minutes to solve 18 problems. How many minutes will it take 6 students
to solve 42 problems?
Make sure to show the correct equation set up, identify your "k" value,

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

d 600 because 15*10*2=300

300+300=600

step-by-step explanation:

the answer should be:

a. 3, 4, and 6

b. 18, 24, and 36

c. 4.8, 6.4, and 9.6

hope i

-lavira : )