A card is chosen at random from a deck of 52 cards. it is replaced and a second card is chosen. what is the probability of choosing a jack and then an eight? p( jack and 8)
answer choices:
A) 16/169
B)1/169
C)16/52
D) 4/52

I believe it would be d. Sorry if I’m wrong

The correct answer is D

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)

Bc equals mb that should be your answer